MATH SOLVE

4 months ago

Q:
# The standard form of the equation of a circle is (xβ3)2+(yβ1)2=16.What is the general form of the equation?

Accepted Solution

A:

[tex]Use:(a-b)^2=a^2-2ab+b^2\\\\(x-3)^2+(y-1)^2=16\\\\x^2-2\cdot x\cdot3+3^2+y^2-2\cdot y\cdot1+1^2=16\\\\x^2-6x+9+y^2-2y+1=16\\\\x^2+y^2-6x-2y+10=16\ \ \ |-16\\\\\boxed{x^2+y^2-6x-2y-6=0}[/tex]