The probability of a spinner arrow stopping on green is 0.25. the probability of drawing a blue 3 from a pack of cards is 0.02. The two events are independent. What is the approximate probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards?
Accepted Solution
A:
Be the event a spinner arrow stopping on green: A The probability of a spinner arrow stopping on green: P(A)=0.25 Be the event drawing a blue 3 from a pack of cards: B The propbability of drawing a blue 3 from a pack of cards: P(B)=0.02 The two events are independent Probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards: P (A and B)=P(A ∩ B)=?
Since the events are independent: P(A ∩ B)=P(A)*P(B) P(A ∩ B)=(0.25)*(0.02) P(A ∩ B)=0.005
Answer: The approximate probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards is 0.005