MATH SOLVE

5 months ago

Q:
# The probability of a spinner arrow stopping on green is 0.25. the probability of drawing a blue 3 from a pack of cards is 0.02. The two events are independent. What is the approximate probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards?

Accepted Solution

A:

Be the event a spinner arrow stopping on green: A

The probability of a spinner arrow stopping on green: P(A)=0.25

Be the event drawing a blue 3 from a pack of cards: B

The propbability of drawing a blue 3 from a pack of cards: P(B)=0.02

The two events are independent

Probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards: P (A and B)=P(A ∩ B)=?

Since the events are independent:

P(A ∩ B)=P(A)*P(B)

P(A ∩ B)=(0.25)*(0.02)

P(A ∩ B)=0.005

Answer: The approximate probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards is 0.005

The probability of a spinner arrow stopping on green: P(A)=0.25

Be the event drawing a blue 3 from a pack of cards: B

The propbability of drawing a blue 3 from a pack of cards: P(B)=0.02

The two events are independent

Probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards: P (A and B)=P(A ∩ B)=?

Since the events are independent:

P(A ∩ B)=P(A)*P(B)

P(A ∩ B)=(0.25)*(0.02)

P(A ∩ B)=0.005

Answer: The approximate probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards is 0.005