MATH SOLVE

4 months ago

Q:
# Submarine a is position at -1100 feet in relation to sea level. Submarine be is position at -800 feet in relation to sea level. Each submarine needs to be 200 feet below sea level in 30 minutes. Which compares the speed at which each submarine needs to travel?

Accepted Solution

A:

Answer:Submarine A needs to travel at 30 feet per minute and the Submarine B at a lower speed, 20 feet per minute. Step-by-step explanation:This is the information given to solve the question:Submarine A position = - 1,100 feet Submarine B position = - 800 feet New position for Submarine A and B = - 200 feetDuration of the travel = 30 minutesDistance that Submarine A need to travel = - 200 + 1,100 = 900 feetDistance that Submarine B need to travel = - 200 + 800 = 600 feetFor calculating the speed, we do this new calculation:Speed Submarine A = Distance that Submarine A need to travel/Duration of the travelSpeed Submarine A = 900 feet/30 minutes Speed Submarine A = 30 feet/minute (Dividing by 30)Speed Submarine B = 600 feet/30 minutesSpeed Submarine B = 20 feet/minute (Dividing by 30)Submarine A needs to travel at 30 feet per minute and the Submarine B at a lower speed, 20 feet per minute.