What is the y-coordinate of the point that divides thedirected line segment from J to k into a ratio of 5:1?75(7,2)++++y =(v2 - y) + va1 2 3 4 5 6 7 8 9 10 11 xOO OOJ (1,-10)

Answer:y-coordinate = 0Step-by-step explanation:Consider the below diagram attached with this question.Section formula:If a point divides a line segment in m:n whose end points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the coordinates of that point are[tex](\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})[/tex]From the below graph it is clear that the coordinates of end points are J(1,-10) and K(7,2). A point divides the line JK is 5:1.Using section formula, the coordinates of that point are[tex](\frac{(5)(7)+(1)(1)}{5+1},\frac{(5)(2)+(1)(-10)}{5+1})[/tex][tex](\frac{35+1}{6},\frac{10-10}{6})[/tex][tex](\frac{36}{6},\frac{0}{6})[/tex][tex](6,0)[/tex]Therefore, the y-coordinate of the point that divides the directed line segment from J to k into a ratio of 5:1 is 0.